All categories

3 years ago

X^2+11x+30 ?????????????????????

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

Solution:

X^2+11x+30

=X^2+(6+5)x+30

=X^2+6x+5x+30

=X(x+6)+5(x+6)

=(X+6)(x+5).

So,the answer is (x+6)(x+5).

You might be interested in

Sale 40% sale price 120$ what is the original price

DedPeter [7]

Answer:

72 is the price after 40% off and the original price is 180$

Step-by-step explanation:

6 0

3 years ago

The equation |2x – 12|= 10 has two solutions.<br> The sum of those two solutions is

zlopas [31]

Answer:

-5 and +5

Step-by-step explanation:

add twelve to both sides

New equations: 2x= -+10

Divide by 2 on both sides

x=-5, +5

3 0

3 years ago

Read 2 more answers

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago

Based on the table, which best predicts the end

juin [17]

Mark you want me to tell him I can send you a photo of the photo you sent you send you

8 0

3 years ago

Drag each function to the correct location on the chart. Classify the functions as continuous and discontinuous functions. If a

Ilia_Sergeevich [38]

Answer:

Continuous: g(x) and j(x)

Removable: h(x) and m(x)

Infinite: f(x) and i(x) and k(x)

Jump: l(x)

Step-by-step explanation:

5 0

3 years ago