Answer:
12<|h-8|<22
Step-by-step explanation:
Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

Putting all the values, we get :

Hence, the minimum allowed length for the runway is 117.33 m.
Add 2 to 3 and get 5 add 3 and get 8 add 5 to get 13 add 8 to get 21
'12' and '48' (choices 'A' and 'D') will both work as common denominators.
The least one is '12' .
Since 4 is a factor of 12, any multiple of 12 is also a multiple of 4 , and can
serve as a common denominator. The smallest multiple of 12 is 12 itself.