1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anastaziya [24]
3 years ago
8

Which are equivalent?

Mathematics
2 answers:
Masteriza [31]3 years ago
6 0

Answer:

Option (a), (d) and (e) are correct.

Step-by-step explanation:

Given : expression 10^x

We have to select the equivalent fractions from the  given options.

We will check each given option one by one,

a) 10\cdot 10^{x-1}

Apply property of exponents, a^b\cdot \:a^c=a^{b+c}

We have, 10\cdot \:10^{x-1}=\:10^{1+x-1}=\:10^x

10\cdot 10^{x-1} is equivalent to given expression 10^x

b) \frac{50^x}{5}

Breaking 50 into factor as 50=5^2\cdot \:2

Thus, =\left(5^2\cdot \:2\right)^x

Apply exponent rule , \left(ab\right)^c=a^cb^c

=\frac{2^x\cdot \:5^{2x}}{5}

Apply exponent rule , \frac{x^a}{x^b}\:=\:x^{a-b}

=2^x\cdot \:5^{2x-1}

\frac{50^x}{5} is not equivalent to given expression 10^x

c) x^5

Clearly seen x^5 is not equivalent to given expression 10^x

d) \:\left(\frac{50}{5}\:\right)^x

Divide 50 by 5 we have 10

So \:\left(\frac{50}{5}\:\right)^x=10^x

\:\left(\frac{50}{5}\:\right)^x is equivalent to given expression 10^x

e) \frac{50^x}{5^x}

Breaking 50 into factor as 50=5^2\cdot \:2

=\frac{2^x\cdot \:5^{2x}}{5^x}

Apply exponent rule , \frac{x^a}{x^b}\:=\:x^{a-b}

=2^x\cdot \:5^{2x-x}

=2^x\cdot \:5^{x}

Apply exponent rule  a^mb^m=\left(ab\right)^m

=2^x\cdot \:5^{x}=10^x

\frac{50^x}{5^x} is equivalent to given expression 10^x

f)  10\cdot 10^{x+1}

Apply property of exponents, a^b\cdot \:a^c=a^{b+c}

We have, 10\cdot \:10^{x+1}=\:10^{1+x+1}=\:10^{x+2}

10\cdot 10^{x+2} is not equivalent to given expression 10^x

Thus, option (a), (d) and (e) are correct.

iris [78.8K]3 years ago
3 0
D and e are equivalent
if you plug in 1,2,3 for X for each equation you can see only d and e are equivalent to the original this is because (50/5)^x and 50^x/5^x simplified is still 10^x
You might be interested in
A store has 15 boxes of apples. Each box contains 98 apples
ICE Princess25 [194]

Answer:

1470

Step-by-step explanation:

because 15×98=1470

6 0
3 years ago
Read 2 more answers
I need help on all three questions provided I'll mark you as the brainiest and friend you.
OLEGan [10]
11. 10^-8 = 1 • 10^-8 in decimal form

12. 6 • 10^-4 = 0.0006 in decimal form

13. n^m turns into 5^4

5 • 5 • 5 • 5 = 625
5^4 = 625
3 0
3 years ago
Read 2 more answers
A) Write a rule for a polynomial with left end up and right end up behavior, and has a y-
Novosadov [1.4K]

Answer:

y = x^2 + 3

Step-by-step explanation:

The equation I put has the left end up, the right end up, and has a y-intercept at (0,3).

If this answer is correct, please make me Brainliest!

7 0
3 years ago
A building that is 100 ft tall casts a shadow that makes a 30 degree angle with the ground. Approximately how long, in feet, is
zhannawk [14.2K]
Rounds to about 58 use the 30 60 90 formula
7 0
4 years ago
Prove that.<br><br>lim Vx (Vx+ 1 - Vx) = 1/2 X&gt;00 ​
faltersainse [42]

Answer:

The idea is to transform the expression by multiplying (\sqrt{x + 1} - \sqrt{x}) with its conjugate, (\sqrt{x + 1} + \sqrt{x}).

Step-by-step explanation:

For any real number a and b, (a + b)\, (a - b) = a^{2} - b^{2}.

The factor (\sqrt{x + 1} - \sqrt{x}) is irrational. However, when multiplied with its square root conjugate (\sqrt{x + 1} + \sqrt{x}), the product would become rational:

\begin{aligned} & (\sqrt{x + 1} - \sqrt{x}) \, (\sqrt{x + 1} + \sqrt{x}) \\ &= (\sqrt{x + 1})^{2} -(\sqrt{x})^{2} \\ &= (x + 1) - (x) = 1\end{aligned}.

The idea is to multiply \sqrt{x}\, (\sqrt{x + 1} - \sqrt{x}) by \displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} so as to make it easier to take the limit.

Since \displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} = 1, multiplying the expression by this fraction would not change the value of the original expression.

\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \lim\limits_{x \to \infty} \left[\sqrt{x} \, (\sqrt{x + 1} - \sqrt{x})\cdot \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}\right] \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}\, ((x + 1) - x)}{\sqrt{x + 1} + \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}}\end{aligned}.

The order of x in both the numerator and the denominator are now both (1/2). Hence, dividing both the numerator and the denominator by x^{(1/2)} (same as \sqrt{x}) would ensure that all but the constant terms would approach 0 under this limit:

\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}.

By continuity:

\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \cdots \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1} \\ &= \frac{1}{\sqrt{1 + \lim\limits_{x \to \infty}(1/x)} + 1} \\ &= \frac{1}{1 + 1} \\ &= \frac{1}{2}\end{aligned}.

8 0
3 years ago
Read 2 more answers
Other questions:
  • Help me with 17.
    11·1 answer
  • What is the LCM of 5 , 17 and 26?​
    10·1 answer
  • If seven x multiple by 3 is 63, what is x?
    15·2 answers
  • Black and Decker Manufacturing sold a set of saws to True Value Hardware. The list price was $3,800. Black and Decker offered a
    11·1 answer
  • 11. Which of the following shows the first 5 terms in
    13·1 answer
  • Find the root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%20%7B%20%7D%5E%7B2%7D%20%7D%20%20%2B%20x%20%2B%20%20%5Csq
    10·1 answer
  • PLZ HELP I WILL GIVE THE BRAINIEST!!
    11·1 answer
  • Can someone help me plss
    7·1 answer
  • What is the scale factor
    10·1 answer
  • Why are angles opposite each other when two lines cross called vertical angles? (
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!