For this case we have the following equation:
(3x + 4) ^ 2-36 = 15x + 20
We can rewrite the equation:
(3x + 4) ^ 2-36 = 5 (3x + 4)
Now we define the following variable:
p = 3x + 4
Substituting the variable in the equation we have:
p ^ 2-36 = 5p
Rewriting:
p ^ 2 - 5p - 36 = 0
Answer:
An equation that is equivalent in terms of p is:
p ^ 2 - 5p - 36 = 0
The answer is to the question is B
Answer:
The differential equation is ![\frac{dx(t)}{dt} = k x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%3D%20k%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
Step-by-step explanation:
From the question we are told that
The number of students are 
The number of student that have contracted the flu is x(t)
The number of student that don't have the flu is mathematically represented as

The rate at which the disease spread is proportional to the number of interactions between students with the flu and students who have not yet contracted it, which can be mathematically represented as
![\frac{dx(t)}{dt} \ \ \ \alpha\ \ \ x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%5C%20%5C%20%5C%20%5Calpha%5C%20%5C%20%5C%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
=> ![\frac{dx(t)}{dt} = k x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%3D%20k%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
Answer:
X = 76*4
= 304 cups of food
Step-by-step explanation:
Given:
- Monkey eat 4 cups of food / day
- Elephants eat 76 times as much as Monkey does / day
So Let X is the number of cups of food that elephants eat per day, we have the equation:
X = 76*4
= 304 cups of food
Hope it will find you well.
Answer:
Answer: 84 meters squared. (i.e. 84m^2).
Step-by-step explanation:
Area of the path = total area of path and plot - plot area only
First, let’s find the area of the plot:
20m x 20m = 400m^2
The path is 1m wide and runs all the way around, so, it describes an ‘outer square’ of 22m x 22m (2 x 1m larger because there are 1m of the path on each side).
The area of this ‘outer square’ is equivalent to the ‘total area of path and plot’
22m x 22m = 484m^2
So:
Area of the path = total area of path and plot - plot area only
= 484 - 400 = 84m^2