If you mean .34 lbs and .13lbs, she would need 2.53
If you meant .34 and 1.3 lbs , she would need 1.36
If actually mean 34 lbs and 13lbs , Kaitlynn has way more than 3 lbs
So,
We are trying to figure out when Grandpa Lopez's age was twice that of Dad.
Let x represent the number of years before/after when G. Lopez's age was twice that of Dad.
66 + x = 2(37 + x)
Distribute.
66 + x = 74 + 2x
Subtract x from both sides.
66 = 74 + x
Subtract 74 from both sides.
-8 = x
So 8 years ago, G. Lopez was twice as old as Dad. Let's check that.
66 - 8 = 58
37 = 8 = 29
29 * 2 = 58
58 = 58
It checks.
Here are the numbers that represent each based on the box plot:
Median: 11 (located at the vertical line in the middle of the box)
Range: 19 - 7 = 12 (highest value - lowest value)
25%: 9 (at the left end of the box)
75%: 14 (at the right end of the box)
Interquartile range: 14 - 9 = 5 (the distance from the beginning to the end of the middle half of the data)
Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer: R = (-19)/2
