<u>To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.</u>
Answer:
<em>x = -9</em>
<em>y = 2</em>
Step-by-step explanation:
<u>Solve the system:</u>
2x + 3y = -12 [1]
2x + y = -16 [2]
Subtracting [1] and [2]:
3y - y = -12 + 16
2y = 4
y = 4/2 = 2
From [1]:
2x + 3(2) = -12
2x + 6 = -12
2x = -18
x = -18/2 = -9
Solution:
x = -9
y = 2
Step-by-step explanation:
Use exponent property of logs.
logb(x²) = 2 logb(x) = 2(0.49) = 0.98
Answer:
67
Step-by-step explanation:
its not a 90!!! tilt your screen.
For this case, the first thing you should know is:
d: v * t
Where,
d: distance
v: speed
t: time
To go to school by bus we have:
d = 45 * t
To return from school we have:
d = 2.5 * (1-t)
how the distance is the same:45 * t = 2.5 * (1-t)
Answer:
the equation that will help find the time it takes chelsea to get to school on the bus is:
45 * t = 2.5 * (1-t)
Note: the equation will have one solution.
Answer:
Vertical Asymptote:
Horizontal asymptote:
it does not exist
Step-by-step explanation:
we are given
Vertical asymptote:
we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf
we know that any log becomes -inf when value inside log is zero
so, we can set value inside log to zero
and then we can solve for x
we get
Horizontal asymptote:
we know that
horizontal asymptote is a value of y when x is +inf or -inf
For finding horizontal asymptote , we find lim x-->inf or -inf
so, it does not exist
