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2 years ago

What does 1+4c=7+2c equal

Mathematics

2 answers:

stiv31 [10]2 years ago

7 0

Answer:

c=3

Step-by-step explanation:

First simplify like terms.

1+4c=7+2c

1+2c=7 (subtract 2c from both sides)

2c=6 (subtract 1 from both sides)

c=3 (divide by 2)

CHECK:

1+4(3)=7+2(3)

1+12=7+6

13=13

Yes!

yuradex [85]2 years ago

4 0

Answer: $c=3$

Step-by-step explanation:

Step 1: Simplify both sides of the equation:

 $4c+1=2c+7$ 

Step 2: Subtract 2c from both sides:

 $4c+1-2c=2c+7-2c$ 

 $2c+1=7$ 

Step 3: Subtract 1 from both sides.:

 $2c+1-1=7-1$ 

 $2c=6$ 

Step 4: Divide both sides by 2:

 $2c/2=6/2$ 

Get your answer:

 $c=3$ 

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Step-by-step explanation:

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2 years ago

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Answer:
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2 years ago

What is the probability of pulling out a red marble then a blue marble?

statuscvo [17]

Answer:

Step-by-step explanation:

Total marble = 8+5+4 = 19

n(Y) = 8, n(B) = 4 and n(R) = 5

Prob(R) = 5/17

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Prob(R and B) = 5/17 × 4/16

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5 0

2 years ago

What is the equation of a line that is parallel to -x+3y=6 and passes through the point (3,5)?

Elena-2011 [213]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

Where:

m: It's the slope

b: It is the cut-off point with the y axis

By definition, if two lines are parallel then their slopes are equal.

We have the following line:

$-x + 3y = 6\\3y = x + 6\\y = \frac {1} {3} x + \frac {6} {3}\\y = \frac {1} {3} x + 2$

Thus, the slope is: $m_ {1} = \frac {1} {3}$

Then $m_ {2} = \frac {1} {3}$

So, the line is of the form:

$y = \frac {1} {3} x + b$

We substitute the point $(x, y) :( 3,5)$ and find b:

$5 = \frac {1} {3} (3) + b\\5 = b$

Thus, the equation is:

$y = \frac {1} {3} x + 5$

Answer:

$y = \frac {1} {3} x + 5$

5 0

2 years ago

Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140

Westkost [7]

Answer:

The amount each took home was 20 unit currency.

Step-by-step explanation:

We are given that Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140 apples, went to market and sold all their apples at the same price, and each received the same sum of money.

Formula : $a \times n + (n - 1)$ , $(a + b)\cdot n + (n - 2)$ , $(a + 2 \cdot b) \cdot n + (n - 3)$ , $(a + 3 \cdot b) \cdot n + (n - 4)$ , $(a + 4 \cdot b) \cdot n + (n - 5)$ , $(a + 5 \cdot b) \cdot n + (n - 6)$ , $(a + 6 \cdot b) \cdot n + (n - 7)$

$a \cdot n + (n - 1) = 20$

$(a + b) \cdot n + (n - 2)=40$

$(a + 2 \cdot b) \cdot n + (n - 3) = 60$

$(a + 3 \cdot b) \cdot n + (n - 4) = 80$

$(a + 4 \cdot b) \cdot n + (n - 5) = 100$

$(a + 5 \cdot b) \cdot n + (n - 6) = 120$

$(a + 6 \cdot b) \cdot n + (n - 7) = 140$

On solving :

n = 7, a = 2, b = 3

So,

$2 \times 7 + 6 = 20$

$5 \times 7 + 5=40$

$8 \times 7 + 4 = 60$

$11 \times 7 + 3 = 80$

$14 \times 7 + 2 = 100$

$17 \times 7 + 1 = 120$

Based on market pricing if groups of apples are sold at 1 unit currency for 7, and extras are sold for 3 unit currency per extra 1, we have the amount :

2×1 + 6×3 = 20

5×1 + 5×3=20

8×1 + 4×3 = 20

11×1 + 3×3 = 20

14×1 + 2×3 = 20

17×1 + 1×3 = 20

20×1 = 20

Therefore, the amount each took home was 20 unit currency.

4 0

3 years ago