ABCD is a square and ABK is an equilateral triangle inside the square,
1 answer:
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Answer:
Solution: (3, 2)
Step-by-step explanation:
It's easier to graph when the equation of the lines are in their slope-intercept form, y = mx + b.
<u>x - 3y = -3</u>
-3y = -x - 3
Divide both sides by -3:
y = 1/3x + 1
where slope = 1/3
y-intercept = 1
<u>x + y = 5</u>
Subtract x from both sides to isolate y:
x - x + y = - x + 5
y = -x + 5
where slope = -1
y-intercept, 5
I started by graphing the y-intercepts of each line. Then, I used the slope of each linear equation (rise over run) to plot the next points on the graph. In the attached screenshot of the graph, <u>x - 3y = -3</u> is the blue line, while <u>x + y = 5</u> is the green line. Their intersection occurs at point, (3, 2).
Therefore, the solution is (3, 2).
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