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Bad White [126]
4 years ago
12

HURRY Please

Mathematics
2 answers:
NemiM [27]4 years ago
7 0

B) The x-intercept indicates all tickets will be sold within 30 minutes

Step-by-step explanation:

From the equation of the function

f(x) = 200 -5x

The domain of f(x) is [0,40] for values of x that are true and the range is [0,200] for values of y from corresponding values of x

The constant 200, is the y-intercept which indicates that at the starting time of selling the tickets, 200 tickets were available

The slope, -5 indicates that the tickets were being sold at a rate of 5 tickets per minute. This shows that in 40 minutes,the 200 tickets will be sold out.

Learn More

To interpret linear functions:brainly.com/question/13599312

Keywords ;theater, ticket, inventory, movie, modeled, function, minutes, elapse, graph, domain, statement, false

#LearnwithBrainly

Leto [7]4 years ago
5 0

Answer:B

Step-by-step explanation: This statement is false. The x-intercept is at( 40,0) it took 40 minutes to sell all the tickets

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3 years ago
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds,What perc
soldier1979 [14.2K]

Answer:

57.62% of players weigh between 180 and 220 pounds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 25

What percent of players weigh between 180 and 220 pounds

We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{25}

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Z = \frac{X - \mu}{\sigma}

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Z = -0.8 has a pvalue of 0.2119

0.7881 - 0.2119 = 0.5762

57.62% of players weigh between 180 and 220 pounds

4 0
3 years ago
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Answer:

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This is the correct answer because I just took the quiz and got 100% on it.

Step-by-step explanation:

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