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Drupady [299]
2 years ago
15

Precal unit 4 sample work-

Mathematics
1 answer:
miv72 [106K]2 years ago
4 0

Answer:

  (3√26, 0)

Step-by-step explanation:

Finish your work by evaluating the sine and cosine. The imaginary part corresponds to the y-coordinate in (x, y) form.

  3√26(cos(360°) +i·sin(360°)) = 3√26(1 +0i)

In rectangular form, that is ...

  (3√26, 0)

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X + y = 20 --> eqn 1
The second equation would be the mass balance shown below:
(x)(0.40) + y(0.70) = 20(0.52) --> eqn 2
Rearranging eqn 1,x = 20 - ySubstitute this to eqn 2:
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Find the area of the isosceles triangle. please help thanks
fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2                      Substitute for b^2 = h^2

24^2 + h^2 = 51^2                   Expand 24^2 and 51^2

576 + h^2 = 2601                    Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025                              Take the square root of both sides

h = 45

Area

Area = 1/2 b * h

Area = 1/2 48 * 45

Area = 1080

Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

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3 years ago
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Alex Ar [27]

Answer:

...?

Step-by-step explanation:

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