If xy=0
assume that at least x or y=0
3(x-3)=0
therefor
3=0 or x-3=0
3=0 is false
therefor
x-3 mus equal zero
x-3=0
add 3 to both sides
x=3
Answer: There is no solution.
Step-by-step explanation:
1.) 1 / 5 (25) + 1 / 5 (-5a) = 4 - a
2.) 5 - a = 4 - a
3.) 5 - a + a = 4 - a + a
4.) 5 = 4
The variable a is completely removed, leaving the final answer as 5 = 4, which isn't true.
Answer:
Step-by-step explanation:
Each equation is in vertex form, so you can easily determine the number of real roots. The leading coefficient tells you whether the parabola opens upward (positive) or downward (negative).
y = a(x -h)^2 +k
has leading coefficient "a" and vertex (h, k).
__
<u>f(x) = 1/3(x +5)^2 +7</u>
vertex: (-5, 7), opens downward
The vertex is above the x-axis, so there are two real roots.
__
<u>f(x) = -5(x -3)^2</u>
vertex: (3, 0), opens downward
The vertex is on the x-axis, so there is one real root.