well first the complement I 90-19=71
and supplement is 180-19=161
The integers are x - 1, x and x + 1
x - 1 + x + x + 1 = 186
3x = 186
x = 186/3 = 62
Therefore, the numbers are 61, 62 and 63
Step-by-step explanation:
2 + 3 × 6 + 4 × 3
Here, Parantheses should be put,
<u>(2 + 3) </u>× 6 + 4 × 3. (P.E.D.M.A.S) ( First Parantheses)
= 5 × 6 + 4 × 3 (Then multiplication)
= 30 + 12. (At last addition)
= 42
Answer:
C. 45 and 141 seconds
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 93 seconds
Standard deviation = 16 seconds
99.7% of running times are approximately between:
By the Empirical rule, within 3 standard deviations of the mean, so between 3 standard deviations below the mean and 3 standard deviations above the mean
3 stnadard deviations below the mean
93 - 3*16 = 45 seconds
3 standard deviations above the mean
93 + 3*16 = 141 seconds
The correct answer is:
C. 45 and 141 seconds
Answer:
I guess that you want to model the elevation of Lake Sam Rayburn.
During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).
If it does not rain, the elevation of the lake decreases by 0.5ft each week.
So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.
L(w) = 165ft - 0.5ft*w
Where w is the number of weeks without rain, if we have 0 weeks without rain, then the level of the lake remains constant at 165ft above sea level,
L(0) = 165ft - 0.
