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yulyashka [42]
3 years ago
8

4x+6<-6 Solve for x put steps

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
4 0

First move the constant to the other side causing it to change sides

4x<-6-6

Then calculate the difference (-6-6)

4x<-12

Now divide both sides by 4

X<-3

Then you are left with your answer:

x<-3

Hope this helps! :3

Reil [10]3 years ago
4 0

Answer:

x < -3

Step-by-step explanation:

4x + 6 < - 6

Taking "6" from Left side of the equation to the right hand side, the sign "=6" changes to "-6", and we get,

4x < - 6 -6

Now, on right hand side, since both signs are same, therefore they add up to get,

4x < - 12

now, divide the complete equation by 4 we get,

4x/4 < -12/4

⇒ x < -3

Thus, the values that x can take are : -4,-5,-6,...-10....-20,....and so on

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Answer:

total 20 squares in matrix of size 4×3

Step-by-step explanation:

in square of size 1×1

six squares of size 2×2

2 squares of size 3×3

3 0
3 years ago
Using the triangle below, find the length of side c if side a is 15 and θ =55. Round your answer to the nearest tenth.
Kaylis [27]

Answer:

15 sin 55 = 12

Step-by-step explanation:

It is a basic trigonometry formula

5 0
3 years ago
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Do you love Selena Quintanilla?
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Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
Y= -4x+9; (-5, ), (2, ), (4, )
olganol [36]
That’s a hard one there
4 0
3 years ago
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