Answer:
<h2>Mjhs needs 189.25 square feet of blue paint, approximately.</h2>Step-by-step explanation:
As you can observe in the image attached, the basketball court is a composite figure formed by a rectangle and half of a circle.
The rectangle has dimensions of 10 feet by 15 feet. The circle has a diameter of 10 feet.
The expression of this composite area would be
Where and
. Replacing these values, we have
Therefore, Mjhs needs 189.25 square feet of blue paint, approximately.
Answer:
The system of equations is :
Equation 1-
Equation 2-
Number of vinyl doghouse = 5
Number of treated lumber doghouse =12.5
Step-by-step explanation:
Let x be the number of vinyl doghouses
y be the number of treated lumber doghouses
→If it takes the company 5 hours to build a vinyl doghouses and 2 hours to build a treated lumber doghouse. The company dedicates 50 hours every week towards assembling and painting doghouses.
Equation 1-
→It takes an additional hour to paint each vinyl doghouse and an additional 2 hours to assemble each treated lumber doghouse. The company dedicates 30 hours every week towards assembling and paining dog houses.
Equation 2-
→When we solve these equation we get the number of vinyl doghouse and treated lumber doghouse.
Subtract equation 2 from equation 1
Put value of x in equation 2
Therefore, number of vinyl doghouse = 5, number of treated lumber doghouse =12.5
Given:
The function for size of a square frame is
where, x is the side length of the picture.
The function for the price in dollars for the frame is
To find:
The single function for the price of a picture with an edge length of x.
Solution:
We know that, for a picture with an edge length of x.
Size of a square frame = f(x)
Price in dollars for the frame = p(x)
Single function for the price of a picture with an edge length of x is
Let the name of this function is c(x). So,
Therefore, the required function is .
Answer:
a) Demand function:
b) The rebate should be of $200, so the sale price becomes $300 per unit.
c) The rebate should be of $150, so the sale price becomes $350 per unit.
Step-by-step explanation:
a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).
We can express the demand function (linear) as:
To calculate the slope m, we use:
To calculate b, we use the known point and the calculated slope:
Then the demand function is:
b) The revenue can be expressed as:
To maximize, we can derive and equal to zero
The rebate should be of $200, so the sale price becomes $300 per unit.
c) If we take into account the cost, we have that
To maximize, we can derive and equal to zero
The rebate should be of $150, so the sale price becomes $350 per unit.