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Vedmedyk [2.9K]
3 years ago
5

Solve the system of equations by elimination. -X + y = -13 -8x - 4y = -8​

Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0

Answer:

X=5, y=-8

Step-by-step explanation:

-X + y =-13 equation 1

-8x-4y=-8 equation 2

4(-x+y)=4(-13). Multiply equation 1 by 4 to eliminate y

-4x + 4y =-52

———————————-

-4x + 4y =-52 equation 1 after multiplying by 4

-8x-4y=-8. Equation 2

-12x=-60 added 2 equations above

x=5

solve for y

-x+y=-13

-5+y=-13

y=-8

Ksivusya [100]3 years ago
3 0
The first one is -2x+15y=-13
The second one is uhhh well I d and K
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What are the solutions of |x+6| greater than or equal to 5? Write the solutions as either the union or the intersection of two s
sukhopar [10]
We have that
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What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

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