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Tanzania [10]
3 years ago
14

Please help!

Mathematics
1 answer:
Ainat [17]3 years ago
8 0
<span>(x – h)^2 + (y – k)^2 = r<span>^2


this equation is a derivative of the equation of a circle

x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y


with h = -3 and k = 1

we can plug in each set of numbers and solve.

we find Z to be on the circle edge!</span></span>
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Based on the information in the diagram, what is the area of AMNP ?<br> 125<br> 100<br> 075<br> 0105
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It’s 100 I solve it and it’s correct
5 0
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Anyone good with algebra 1?
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Replace x with 7:

y = 115 + 10(7)

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Let f(x) = 12/4x+2 Find f(-1). (1 point)
noname [10]

Answer:

-1

Step-by-step explanation:

let,x=-1

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3 0
3 years ago
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4 0
2 years ago
Read 2 more answers
the world population was 2560 million in 1950 and 6,080 million in 2000. assume the growth rate of the population P'(t) is propo
tatyana61 [14]
Let P(t) denote the population at time t in millions.

The population's growth rate is modeled by the differential equation

P'(t)=kP(t)

This equation is separable, and we can solve easily:

\dfrac{\mathrm dP(t)}{\mathrm dt}=kP(t)\iff\dfrac{\mathrm dP(t)}{P(t)}=k\,\mathrm dt
\implies\displaystyle\int\frac{\mathrm dP}P=k\int\mathrm dt
\implies \ln|P(t)|=kt+C
\implies P(t)=e^{kt+C}=e^{kt}e^C=Ce^{kt}

Let's assume 1950 corresponds to year t=0, so that 2000 would correspond to t=50. Then P(0)=2560, which means we have

2560=Ce^{0k}=C

and P(50)=6080, which means

6080=2560e^{50k}\implies \dfrac{19}8=e^{50k}
\implies 50k=\ln\dfrac{19}8
\implies k=\dfrac1{50}\ln\dfrac{19}8\approx0.0173

So the population is modeled by

P(t)=2560e^{0.0173t}

(assuming t=0 refers to the year 1950)
4 0
3 years ago
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