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Nezavi [6.7K]
3 years ago
12

Let f(x) = 12/4x+2 Find f(-1). (1 point)

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

let,x=-1

f(x)= 12/4x + 2

f(-1)= 12/4x(-1) + 2

=12/(-4) +2

= -3+2

= -1

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Find LCM x⁴-y⁴,x²-y² and x³-y³​
Fynjy0 [20]

Answer:

Step-by-step explanation:

1st expression: x⁴-y⁴

= (x²)² - (y²)²

= (x² +y²)(x² -y²)

= (x² +y²)(x +y)(x -y)

= (x +y)(x -y)(x² +y²)

2nd expression: x² -y²

= (x +y)(x -y)

3rd expression: x³ -y³

= (x -y)(x² +xy +y²)

Now ,

Lowest Common Multiples (L.C.M.) = common factors * rest factors

= (x+y)(x-y) * (x² +y²)(x² +xy +y²)

= (x² -y²)(x²+y²) * (x² +xy +y²)

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8 0
3 years ago
Solve the quadratic equation by completing the square. 3x2 - 6x - 4 = 0
lakkis [162]

Answer:

The solutions are

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x=1-\sqrt{\frac{7}{3}}

Step-by-step explanation:

we have

3x^{2}-6x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

3x^{2}-6x=4

Factor the leading coefficient

3(x^{2}-2x)=4

Complete the square. Remember to balance the equation by adding the same constants to each side

3(x^{2}-2x+1)=4+3

3(x^{2}-2x+1)=7

Rewrite as perfect squares

3(x-1)^{2}=7

(x-1)^{2}=\frac{7}{3}

square root both sides

x-1=(+/-)\sqrt{\frac{7}{3}}

x=1(+/-)\sqrt{\frac{7}{3}}

x=1+\sqrt{\frac{7}{3}}

x=1-\sqrt{\frac{7}{3}}

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3 years ago
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Gradient=rise/run=y2-y1/x2-x1

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As you can't divide by zero the line's equation is x=-4 so it doesn't have a gradient as such. However, a parallel line would be the y-axis
3 0
3 years ago
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Answer:

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5 0
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