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kakasveta [241]
3 years ago
13

What is the solution to the system that is created by the equation y=-x+6 and the graph shown below?

Mathematics
2 answers:
34kurt3 years ago
6 0
1st let/s find the equation of the graph shown. It has te form of y₁ =mx since it oases by the origin. Moreover we notice that the slope m = rise/run = 1/2. hence the equation IS y₁ = (1/2)x.
To find the solution of y₁ = 1/2 x and y= -x + 6, let's y=y₁

-x + 6 = 1/2 x ↔ -2x +12 = x ↔ -3x= -12  and x = 4. For x = 4 , y =2.

And the solution is the intersection point between y and y₁ which is nothing but the solution or te coordinate of this point that is (4,2)
mina [271]3 years ago
3 0
The graph graphed is y=1/2x

so
y=1/2x and y=-x+6
y=y so
1/2x=-x+6
times 2 both sides
x=-2x+12
add 2x both sides
3x=12
x=4

sub back
y=1/2x
y=1/2(4)
y=2

(4,2) is the solution
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viva [34]

Answer:

Step-by-step explanation:

rule for line c: y=x+3

x  y

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1  4

2  5

3   6

I was able to determine the rule because line c has a slope (m) of 1 (it goes up one and sideways one each time). Its y int. is at 3, so that means 3 is b in the equation y= mx+b

Rule for line D: y=1/2x

x y

0 0

2 1

4 2

6 3

Line d is y=1/2x becaise it goes up 1 and then sidewys 2, so slope (m)= 1/2. There is no b becase it crosses the origin.

(-2,-1) (-4,-2) (-6, -3) just extend the line with a ruler.

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3 0
3 years ago
What is the answer to <br> 2x=24
Digiron [165]

Answer:

12

Step-by-step explanation:

you divide 24 by 2 because it is multiplication, and the opposite is division.

5 0
3 years ago
Read 2 more answers
(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
frutty [35]

Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

4y''=-25y

For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

4 0
3 years ago
Hey, please help me thanks
rjkz [21]

Answer:

240

Step-by-step explanation:

7 0
3 years ago
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after Barbara fills each of her 4 squirrel feeders with 2 2/3 cups of peanuts she has 1 3/4 cups of peanuts left. how many cups
dybincka [34]
12 5/12 would be your answer
6 0
3 years ago
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