34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.
Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. 
Here μ to μ + σ = 
Hence 34% of the scores lie between 433 and 523.
Answer:
1/6
Step-by-step explanation:
The slope is the number in front of the x.
Answer:
1 .4x2-9= 2x+3,2x-3
2 .16x2-1=4x-1,4x+1
3 .16x2-4=4(2x+1)(2x-1)
4 .4x2-1=(2x+1)(2x-1)
Step-by-step explanation:
16x² − 1 = (4x − 1)(4x + 1) ; 16x² − 4 = 4(2x + 1)(2x − 1); 4x² − 1 = (2x + 1)(2x − 1) ;
4x² − 9 = (2x + 3)(2x − 3)
16x² − 1 is the difference of squares. This is because 16x² is a perfect square, as is 1. To find the factors of the difference of squares, take the square root of each square; one factor will be the sum of these and the other will be the difference.
The square root of 16x² is 4x and the square root of 1 is 1; this gives us (4x-1)(4x+1).
16x² − 4 is also the difference of squares. The difference of 16x² is 4x and the square root of 4 is 2; this gives us (4x-2)(4x+2). However, we can also factor a 2 out of each of these binomials; this gives us
2(2x-1)(2)(2x+1) = 2(2)(2x-1)(2x+1) = 4(2x-1)(2x+1)
4x² − 1 is also the difference of squares. The square root of 4x² is 2x and the square root of 1 is 1; this gives us (2x-1)(2x+1).
4x² − 9 is also the difference of squares. The square root of 4x² is 2x and the square root of 9 is 3; this gives us (2x-3)(2x+3).
First, we find the slope
(4,0)(0,-3)
slope = (-3 - 0) / (0 - 4) = -3/-4 = 3/4
there can be 3 possible answers for this..
y - y1 = m(x - x1)
slope(m) = 3/4
using points (4,0)...x1 = 4 and y1 = 0
now we sub
y - 0 = 3/4(x - 4) <== this is one answer
y - y1 = m(x - x1)
slope(m) = 3/4
using points (0,-3)...x1 = 0 and y1 = -3
now we sub
y - (-3) = 3/4(x - 0) =
y + 3 = 3/4(x - 0) <== here is another answer
y - y1 = m(x - x1)
slope(m) = 3/4
using points (-4,-6)...x1 = -4 and y1 = -6
now we sub
y - (-6) = 3/4(x - (-4) =
y + 6 = 3/4(x + 4) <=== and here is another answer
