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Jet001 [13]
3 years ago
8

Last summers, students who worked earned an average of $80 a week with a standard deviation of $12. What percentage of students

earned more that $104 per week?
Mathematics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

  • 2.28%

Step-by-step explanation:

<u>Given:</u>

  • μ = 80
  • σ = 12
  • x = 104

<u>Find z-score:</u>

  • z = (x - μ)/σ
  • z = (104 - 80)/12 = 2

Percent value corresponding to 2 as per z-table is 0.9772. This is corresponding to 97.72%.

<u>Percentage of students earned more than $104:</u>

  • 100 - 97.72 = 2.28
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julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

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Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

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Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

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Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

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Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

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Step-by-step explanation:

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We divide through by 6000 to obtain,

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This implies that,

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We take the square root of both sides,

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This gives us,

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Multiply through by 100 to obtain;

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iVinArrow [24]
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