Last summers, students who worked earned an average of $80 a week with a standard deviation of $12. What percentage of students
earned more that $104 per week?
1 answer:
Answer:
Step-by-step explanation:
<u>Given:</u>
<u>Find z-score:</u>
- z = (x - μ)/σ
- z = (104 - 80)/12 = 2
Percent value corresponding to 2 as per z-table is 0.9772. This is corresponding to 97.72%.
<u>Percentage of students earned more than $104:</u>
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2nd blank- 3.6
3rd blank- 1.4
Step-by-step explanation: you have to plug in the y and subtract by the last number to get x
Answer:
$511.575
Step-by-step explanation:
Given data
P=$475
R=3.8%
T= 2 years
Compound interest
A=P(1+r)^t
substitute
A=475(1+0.038)^2
A=475(1.038)^2
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Hence the final amount is $511.575
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Correct answer
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Step-by-step explanation:
2129 + 2348 + 1863 = 6340
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