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frozen [14]
3 years ago
6

A set of stickers contains 4 hearts for every 6 stars. Which choice contains an equivalent ratio of hearts to start?

Mathematics
2 answers:
Yuri [45]3 years ago
7 0

Answer:

6 hearts to 9 stars

Step-by-step explanation:

Ad libitum [116K]3 years ago
3 0

Answer:

I believe it would be 6 hearts to 9 stars

Step-by-step explanation:

explanation #1

4 hearts to 6 stars can be reduced, which makes 2 hearts to 3 stars. so you go from 2 hearts : 3 stars to 4 hearts : 6 stars then you would get to 6 hearts : 9 stars.

explanation #2

4:6 can be reduced which equals 2:3. the difference between 2 and 4 is 2 and the difference from 3 and 6 is 3. so 6:9 would be after 4:6

hopefully this helps!

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IceJOKER [234]
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6 0
3 years ago
Read 2 more answers
Help me out please i will give branliest and 25 points !!!
Margarita [4]

Answer:

Answers A (1/3), C (4/15) and D (5/6) are all repeating decimals.  

Step-by-step explanation:

Repeating decimals are decimals in which a number or sequence of numbers is repeated over and over when dividing the numerator by the denominator of a fraction.  For example, when you divide 1 by 3 (1/3), you will get a repeating decimal of 0.3333...since 3 goes into 10 three times with a remainder of 1 and will keep going.  Likewise, when you divide 4/15, you get an initial value of 0.2, with a repeating 6, or 0.266666...  Lastly, when you divide 5/6, you will get a repeating decimal of 0.833333....  The other answers will all be terminating decimals when you divide the numerator by the denominator.  Terminating decimals mean the stop at some point and don't continue.  

6 0
3 years ago
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Use induction to prove that 2 divides n^2 n whenever n is a positive integer
andrey2020 [161]

Answer:

that's wrong

Step-by-step explanation:

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5 0
3 years ago
Rachel and three friends were going to the movies. Each ticket cost $10.50 and then they bought 2 popcorns at $3.50 each, and th
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8 0
3 years ago
Two friends race against each other in 100-meter and 800-meter races. Of the 200 races they ran this year, the wins, losses, and
docker41 [41]
<span>Let makes the table neater. event D= 100m, even E=800m
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A won the race (Event A)     30           50
B won the race (Event B)     60           25 
A and B tied (Event T)          10            25</span>

B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
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The difference would be 75%-40%=35% more likely to lose 800-m race
4 0
3 years ago
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