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4 years ago

Na(g) + C(g) > __NaCl(g)

Chemistry

1 answer:

Vlada [557]4 years ago

3 0

Answer:

2.35 L

Explanation:

Given data:

Mass of sodium metal = 4.81 g

Volume of Cl react at STP= ?

Balance chemical equation = ?

Solution:

Balance chemical equation:

2Na + Cl₂ → 2NaCl

Number of moles of Na:

Number of moles = mass/ molar mass

Number of moles = 4.81 g/ 23 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of sodium and chlorine from balance chemical equation.

Na : Cl₂

2 : 1

0.21 : 1/2×0.21 = 0.105 mol

Volume of Cl₂:

PV = nRT

standard temperature = 273 K

standard pressure = 1 atm

R = general gas constant = 0.0821 atm.L/mol.K

n = moles = 0.105 mol

Now we will put the values.

V = 0.105 mol × 0.0821 atm.L/mol.K × 273 K / 1 atm

V = 2.35 L/ 1

V = 2.35 L

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4 years ago

1. A calorimeter contains 143 g of water at 22.5°C. A 12 g sample of NaCl is added to the water in the calorimeter. After the so

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Answer:

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Explanation:

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The enthalpy of solution will be equal to the heat change in the solution.

The heat change of solution will be calculated as:

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4 years ago

A 500 mL hypertonic saline solution is labeled as consisting of 5.21 % w/w NaCl. Given that the density of salt water is 1.02 g/

kicyunya [14]

Answer: The molarity of saline solution is 0.909 M

Explanation:

We are given:

5.21 w/w % NaCl

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$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

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Putting values in above equation, we get:

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$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of NaCl = 5.21 g

Molar mass of NaCl = 58.44 g/mol

Volume of solution = 98.04 mL

Putting values in above equation, we get:

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Hence, the molarity of saline solution is 0.909 M

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3 years ago

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3 years ago

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Explanation:

4 0

3 years ago

__Na(g) + __C(g) > __NaCl(g)

Na(g) + C(g) > __NaCl(g)