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Gekata [30.6K]
2 years ago
8

In eukaryotes, the process of cell division is called mitosis true or false quick pls :)

Chemistry
1 answer:
mamaluj [8]2 years ago
6 0
True. Mitosis is a part of the call cycle when replicated chromosomes are separated into new nuclei. It is a for if eukaryotic cell division that produces two daughter cells with the same genetic components as the parent cells.
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1 Which scientist first said that "elements are made up of identical atoms
babunello [35]

Answer:

John Dalton

Explanation:

4 0
3 years ago
why would air moving over a cold current cause fog (advection fog)? group of answer choices the cold current produces the fog wh
frutty [35]

The correct answer is option  C.

The air moving over a cold current cause fog or advection fog when the air is chilled, which decreases the capacity of air to hold water vapor, and eventually, the relative humidity reaches 100% - leading to condensation and fog formation.

What is advection fog?

When warm- moist air or warm air front slides over the cold air front or cold surface, it results in the formation of advection fog.

Resultantly, the air becomes saturated and chilled at high humidity levels due to which water vapors start to condense leading to fog formation.

Moreover, the optimal condition for the formation of advection fog is cloudy windy weather having moderate to powerful winds.

If you want to learn more about advection fog click here:

brainly.com/question/18803983

#SPJ4

The complete question is:

Why would air move over a cold current cause fog (advection fog)?

(a)  the cold current produces the fog when kelp beds release condensation nuclei.

(b)  the cold current produces the fog by mixing with the air.

(c) the air is chilled, which decreases the capacity of air to hold water vapor, and eventually, the relative humidity reaches 100% - leading to condensation and fog formation.

7 0
1 year ago
How would a system in which both matter and energy are exchanged freely between the system and the surroundings be classified? (
Nata [24]

Answer:

An open system

Explanation:

An open system is a system in which both matter and energy are exchanged freely between the system and the surroundings.

An example is a pot of water boiling on the stove. The surroundings (the stove) can supply heat energy to the water and the water can escape into the atmosphere.

A <em>closed system</em> is a system in which energy but not matter is exchanged freely between the system and the surroundings.

An example is a pressure cooker on the stove. The surroundings (the stove) can supply heat energy to the food inside, but no matter can escape through the closed lid.

An <em>isolated system</em> is a system in which neither energy nor matter can be exchanged between the system and the surroundings.

An example is a thermos of hot soup. The cap prevents matter from escaping and the shiny interior reflects heat back into the soup.

8 0
3 years ago
A 19.0 L helium tank is pressurized to 26.0 atm. When connected to this tank, a balloon will inflate because the pressure inside
vesna_86 [32]

Answer:

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Explanation:

Assuming Helium behaves like an ideal gas and temperature is constant.

According to Boyle's law for ideal gases, at constant temperature,

P₁V₁ = P₂V₂

P₁ = 26 atm

V₁ = 19.0 L

P₂ = 1 atm (the balloon is said to expand till the pressure matches the pressure of the atmpsphere; and the pressure of the atmosphere is 1 atm)

V₂ = ?

P₁V₁ = P₂V₂

(26 × 19) = 1 × V₂

V₂ = 494 L (it is assumed the balloon never bursts)

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Hope this Helps!!!

6 0
3 years ago
How many days does it take 16.Og of Gold-198 to decay to 1.0g? (each half-
forsale [732]

Answer:

10.8 days (3 sig.figs.)

Explanation:

All radioactive decay is 1st order decay defined by the expression A = A₀e^-kt

which is solved for time of decay (t) => t = ln(A/A₀) / -k

A = final weight = 1.0 gram

A₀ = initial weight = 16.0 grams

k = rate constant = 0.693/t(1/2) = 0.693/2.69 days = 0.258 days⁻¹

t = ln(1/16) / -0.258da⁻¹ = (-2.77/-0.258) days = 10.74646792 days (calculator)

≅ 10 days (1 sig. fig. based on given 1 gram mass)

4 0
2 years ago
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