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Ad libitum [116K]
3 years ago
12

DECISION SCIENCE Assume more restrictions. The books pass through two departments: Graphics and Printing, 1. before they can be

sold, X requires 3 hours in Graphics and 2 hours in printing. Y requires 1 hour in graphics and 1 hour in printing. There are 21 hours available in graphics and 19 hours in printing respectively. Solve for x and y.

Mathematics
1 answer:
STALIN [3.7K]3 years ago
6 0

Answer: The value of x and y are 2 and 15 respectively.

Step-by-step explanation:

Since we have given that

Number of hours available in graphics = 21 hours

Number of hours in printing = 19 hours

Number of hours required by x in graphics = 3

Number of hours required by x in printing = 2

Number of hours required by y in graphics = 1

Number of hours required by y in printing = 1

According to question, we get that

3x+y=21\\\\2x+y=19

Using the graphing method, we get that

x = 2 and y = 15

Hence, the value of x and y are 2 and 15 respectively.

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What is 2/3+4/5 simplified ?
11Alexandr11 [23.1K]

Answer:

\frac{2}{3}  +  \frac{4}{5}

=  \frac{10 + 12}{15}

=  \frac{22}{15}

= 1 \frac{7}{15}

6 0
4 years ago
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5, 3, 7,0-2,-1, -7 1-5 least to greatest<br>​
ANTONII [103]
-7, -2, -1, 0, 3, 5, 7
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3 years ago
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HELP PLSSSSSS MATH :(
FrozenT [24]

Answer:

1. (2,3)

2. (7,-2)

3. (-4,-1)

4. No solutions

Step-by-step explanation:

Solve using substitution or elimination.

4 0
3 years ago
Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c
steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

Compute the sample proportions as follows:

\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23

The critical value of <em>z</em> for 90% confidence interval is:

z_{0.10/2}=z_{0.05}=1.645

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0
3 years ago
In how many orders can six people line up from left to right for a group photo?
slavikrds [6]

Answer:

720 possible orders

Step-by-step explanation:

To order 6 people in a line, let's imagine them as 6 possible spaces:

( )( )( )( )( )( )

Going from left to right, let's start with space 1.

There are 6 possibilities for space 1 as any of the 6 people could occupy that space in the line.

(6)( )( )( )( )( )

Next, since one person will have already occupied space 1, there are only 5 people left who can occupy space 2, so there are 5 possibilities for space 2:

(6)(5)( )( )( )( )

Continuing in this fashion, there are now only 4 people left so 4 possibilities for space 3 and etc.

(6)(5)(4)(3)(2)(1)

This means we have 6,5,4,3,2 and 1 possibilities for each space respectively.

Multiply them together and we have:

6x5x4x3x2x1 = 720 possible orders.

Hope this helped!

5 0
3 years ago
Read 2 more answers
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