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Airida [17]
4 years ago
15

15 percent of $9 is $

Mathematics
1 answer:
TiliK225 [7]4 years ago
8 0
$1.35 is the answer.
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A bee flies 25 m north of the hive then 10 m east 5 m west and 10 m south. How far north and east of the hive is it now? Explain
mafiozo [28]

Answer:

20 meters north.

Step-by-step explanation:

(I did it on a paper not to lose track.) First we go 25 north. Then ten east. Five south. And 10 west again. So in East/West we didn't move but we moved 5 down/south so we are still at twenty. If you don't understand still draw it on a paper.

5 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
What is six hundred eighty one million, seven hundred thousand in digit
Natasha2012 [34]
681,700,000 just like that six hunnit eight juan mill sebn hunnit thousand 

4 0
3 years ago
Which is the best estimate for the length of a lady bug?
Effectus [21]

Answer:

The average length of a ladybug is . 3 to . 4 inches.

7 0
3 years ago
Express this in standard form 5.4×10^1​
Naily [24]
Well it would just be 54 since you just need to move the decimal over by 1.

So 5.4x10= 54
7 0
4 years ago
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