Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Answer:
test statistic, z = −1.74
Step-by-step explanation:
given data
students n = 100
mean time x = 41.13 seconds
σ = 5
we consider µ = 42
solution
we get here The test statistic that is express as
test statistic, z = 
......................1
put here value and we will get
test statistic, z = \frac{41.13-42}{\frac{5 }{\sqrt{100}}}
test statistic, z = −1.74
Answer:
a = -5
Step-by-step explanation:
Answer:
a. 0.81818182
b. 0.8
c. -3.4
d. 0.55555556
Step-by-step explanation:
Your answer is c ur welcome
