3 years ago

Which container could logically have a capacity of 1,000 liters?

Mathematics

1 answer:

Ahat [919]3 years ago

8 0

A kitchen sink would be close to 1000 liters

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Here’s a graph of a linear function. Write the equation that describes that function. Express it in slope intercept form.

MatroZZZ [7]

Answer:

y = $\frac{3}{4\\}$ x + 2

Step-by-step explanation:

To find the slope:

Find two spots where the line intersects and exact point. (-8,-4)(-4,-1)

Either count up & over or do y1-y2 / x1-x2 (-4+1)/(-8+4) -3/-4 3/4

The intercept is where it crosses the y-axis, in this case 2

Write the equation like this y = mx + b where m=slope & b=intercept

y = 3/4x + 2

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3 years ago

You put 15 gallons of gasoline in your car, you know that this amount of gasoline will allow you to drive about 450 miles?

solmaris [256]

i dont get wht u are trying to say?

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3 years ago

A student was asked to use the formula for the perimeter of a rectangle, P = 2l + 2w, to solve for l. The student came up with a

Mekhanik [1.2K]

The student solved for 2l, not l. Dividing <span>P -2w=2l by 2, we get l=P/2-w</span>

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3 years ago

Gina has 7 2/6 ft of silver ribbon and 2 4/6 of gold ribbon how much more silver ribbon does Gina have than gold ribbon?

salantis [7]

Answer:

Gina has 5 more feet of silver ribbon than gold

Step-by-step explanation:

7 - 2 =5

7 0

3 years ago

From a plane flying due east at 265 m above sea level, the angles of depression of two ships sailing due east measure 35 degrees

ivann1987 [24]

Answer:

189.8 m

Step-by-step explanation:

See the diagram attached.

Now, the plane is at B and the two ships are at C and at D.

So, angle of depression of C from B is ∠ OBC = ∠ ACB = 35°

Again, the angle of depression of D from B is ∠ OBD = ∠ ADB = 25° ,

Now, from the right triangle Δ ACB,

$\tan 35 = \frac{AB}{AC} = \frac{265}{AC}$

⇒ $AC = \frac{265}{\tan 35} = 378.5$ m.

Similarly, from the right triangle Δ ADB,

$\tan 25 = \frac{AB}{AD} = \frac{265}{AD}$

⇒ $AD = \frac{265}{\tan 25} = 568.3$ m.

Hence, the distance between the ships = CD = AD - AC = 568.3 - 378.5 = 189.8 m (Approx.) (Answer)

5 0

3 years ago