Answer:
like
Step-by-step explanation:
No 1+1 does not equal fish.....I thought so too until I looked it up
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Y = 5x + 5
y - x = 5
You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:
y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0
Substitute your value for x into one of the original equations to y:
y = 5x + 5
y = 5(0) + 5
y = 5
Finally, substitute both values into both original equations to check your work:
5 = 5(0) + 5 --> 5 = 5 <--True
5 - 0 = 5 --> 5 = 5 <--True
Answer:
x = 0
y = 5
