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Archy [21]
3 years ago
11

What are two numbers that multiply to get -64 , but when added get 0?

Mathematics
1 answer:
vodomira [7]3 years ago
5 0
The simplest way in solving this is to find the factors of 64, and its corresponding negative values.

So, x = {1, 2, 4, 8, 16, 32, 64}
So its corresponding x values to get -64 are:
x = {-64, -32, -16, -8, -4, -2, -1}

Now, we notice that 8 and -8 are the same magnitude, with opposite signs. That means when they are added, they will cancel.

Hence, your two numbers are 8 and -8

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Larry bought 24 marbles little lost half of his marbles how many did he lose​
emmasim [6.3K]

Answer:

12

Step-by-step explanation:

his he had lost 12 of his marbles then he would only have 12 left to begin with.

to do this we can do the equation:

24/0.5 (the 0.5 is the represent that the 24 marbles had been split into two, a half for each party)

this would then give use our quotient of 12 marble he had lost

3 0
3 years ago
What fraction is shaded and what percentage is shaded
olganol [36]

Answer:

a) 6/9

b) 66.66%

Step-by-step explanation:

a) Total number of the small triangles inside the big triangle=9

and the shades = 6

friction of shaded = 6÷9

b) percentage of shaded = 6÷9 ×100

=66.6666%

4 0
3 years ago
What property does the equation 4+x+7=4+7+x
e-lub [12.9K]
Transitive property of addition 

6 0
3 years ago
Consider a particle moving around a circle with a radius of 38cm. It rotates from 10 degrees to 100 degrees in 11 seconds. Calcu
kifflom [539]

Step-by-step explanation:

Given that,

Radius of circle, r = 38 cm = 0.38 m

It rotates form 10 degrees to 100 degrees in 11 seconds i.e.

\theta_i=10^{\circ}=0.174\ rad

\theta_f=100^{\circ}=1.74\ rad

Let \omega is the angular velocity of the particle such that, \omega=\dfrac{\omega_f-\omega_i}{t}

\omega=\dfrac{1.74-0.174}{11}

\omega=0.142\ rad/s

We need to find the instantaneous velocity of the particle. The relation between the angular velocity and the linear velocity is given by :

v=r\times \omega

v=0.38\times 0.142

v = 0.053 m/s

So, the instantaneous velocity of the particle is 0.053 m/s. Hence, this is the required solution.  

6 0
3 years ago
PLEASE SHOW WORK ILL GIVE BRAINLIEST DUE TODAY!!!
murzikaleks [220]

Answer:

1. 169     2. 163      3. 54       4. 221      5. 6         6. 7         7. 11        8. 9

Step-by-step explanation:

Remember the Order of Operations:

Parentheses

Exponents

Multiplication

Division

Addition

Subtract

*But always solve from left to right so there can be times where you either have to do division before multiplication or subtraction before addition

1. 14 + <u>18 ÷ 2 </u>x 18 – 7

14+<u>9 x 18</u>-7

<u>14+162</u>-7

176-7

169

2. <u>15 x 10</u> + 12 ÷ 3 + 9

150+<u>12÷3</u>+9

<u>150+4</u>+9

154+9

163

3. <u>8 x 4</u> + 9 – 9 + 18

<u>36+9</u>-9+18

<u>45-9</u>+18

36+18

54

4. 2 - 1 +<u> 5 x 4 </u>x 11

2-1+<u>20x1</u>1

<u>2-1</u>+220

1+220

221

5. 60 – <u>9 x 8</u> ÷ 8 x 6

60-<u>72÷ 8</u> x 6

60-<u>9x6</u>

60-54

6

6. <u>(10 ÷ 5)</u>3 + 100 – 9 x 11

<u>(2)3</u>+100-9x11

6+100-<u>9x11</u>

<u>6+100</u>-99

106-99

7

7. <u>3 x 8</u> x 2 – 42 + 5

<u>24x2</u>-42+5

<u>48-42</u>+5

6+5

11

8. <u>14 ÷ 2</u> -1 + 3

<u>7-1</u>+3

6+3

9

6 0
3 years ago
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