Answer:
BC ≈ 14.5 cm
Step-by-step explanation:
Using the sine ratio in the right triangle
sin65° =
=
=
( multiply both sides by 16 )
16 × sin65° = BC , then
BC ≈ 14.5 cm ( to the nearest tenth )
Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Answer:
61
Step-by-step explanation:
1. let the unknown be x
2. using theorem of Pythagoras that states the hypotenuse will be equal to the sum of the other two sides we can determine that 75=14+X
3. this implies that X=75-14
4. therefore X= 61
An algebraic expression is an expression that includes constants, variables, and the algebraic operations (add, subtract, multiply, divide.
Answer:
x=7
Step-by-step explanation:
14/28=x/14
x=7