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uysha [10]
4 years ago
14

class of 24 students 7/8 are allowed to attend recess on Friday how many students will be allowed to attend recess

Mathematics
2 answers:
loris [4]4 years ago
7 0
If you would like to know how many students will be allowed to attend recess on Friday, you can calculate this using the following steps:

7/8 of 24 students = 7/8 * 24 = 7 * 3 = 21 students

Result: 21 students will be allowed to attend recess on Friday.
tatuchka [14]4 years ago
4 0
21 students are able to attend recess on Friday. Take 24 and multiply it by 7/8 
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0.45m-9=0.9m, what is the least power of ten you could multiply by to write an equivalent equation with integer coefficients?
tia_tia [17]

Answer:

m = -20

Step-by-step explanation:

Step 1 :

9

Simplify ——

10

Equation at the end of step 1 :

45 9

((——— • m) - 9) - (—— • m) = 0

100 10

Step 2 :

9

Simplify ——

20

Equation at the end of step 2 :

9 9m

((—— • m) - 9) - —— = 0

20 10

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 20 as the denominator :

9 9 • 20

9 = — = ——————

1 20

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

9m - (9 • 20) 9m - 180

————————————— = ————————

20 20

Equation at the end of step 3 :

(9m - 180) 9m

—————————— - —— = 0

20 10

Step 4 :

Step 5 :

Pulling out like terms :

5.1 Pull out like factors :

9m - 180 = 9 • (m - 20)

Calculating the Least Common Multiple :

5.2 Find the Least Common Multiple

The left denominator is : 20

The right denominator is : 10

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

2 2 1 2

5 1 1 1

Product of all

Prime Factors 20 10 20

Least Common Multiple:

20

Calculating Multipliers :

5.3 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

5.4 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 9 • (m-20)

—————————————————— = ——————————

L.C.M 20

R. Mult. • R. Num. 9m • 2

—————————————————— = ——————

L.C.M 20

Adding fractions that have a common denominator :

5.5 Adding up the two equivalent fractions

9 • (m-20) - (9m • 2) -9m - 180

————————————————————— = —————————

20 20

Step 6 :

Pulling out like terms :

6.1 Pull out like factors :

-9m - 180 = -9 • (m + 20)

Equation at the end of step 6 :

-9 • (m + 20)

————————————— = 0

20

Step 7 :

When a fraction equals zero :

7.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

-9•(m+20)

————————— • 20 = 0 • 20

20

Now, on the left hand side, the 20 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

-9 • (m+20) = 0

Equations which are never true :

7.2 Solve : -9 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

7.3 Solve : m+20 = 0

Subtract 20 from both sides of the equation :

m = -20

One solution was found :

m = -20

6 0
3 years ago
Write an equation of the line that passes through (−5, −2)(−5, −2) and is parallel to y=23x+1y=23x+1.
Klio2033 [76]
Assuming you meant 2/3
y=2/3x+1 and (-5,-2)

paralell means same slope
y=mx+b
m=slope

y=2/3x+1
sllope=2/3

point slope
y-y1=m(x-x1)
for slope=m
a point is (x1,y1)

slope=2/3
point=(-5,-2)

y-(-2)=2/3(x-(-5))
y+2=2/3(x+5)
or
y=2/3x+16/3

7 0
3 years ago
Please awnser this one 2
almond37 [142]
The answer to the problem is c
3 0
3 years ago
Read 2 more answers
Which pair of numbers does the square root of 5 fall between
Olenka [21]
2.2 and 2.3 SO Take 2/5 and that what you get





8 0
3 years ago
Read 2 more answers
One number is five more than three times another. If their difference is 35, what is the larger number?
miv72 [106K]
Let x and y be the two unknown numbers. If one number, say x,is 5 more than 3 times another, say y, the equation would be

x = 5 + 3y

When their difference is 35, x-y = 35, since x is the much larger number here. We substitute x to solve for the smaller number, y.

x - y = 35
(5 + 3y) -y = 35
5 +2y = 35
2y = 35-5
2y = 30
y = 15

The larger number x would be
x = 5 + 3(15)
x = 50

The answer is 50.


8 0
3 years ago
Read 2 more answers
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