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3 years ago

What is the next number in the sequence? Explain your reasoning.

1 answer:

5 0

1,4,7,10,13,16 $a_{n+1}=a_{n}+3$
1,5,9,13,17,21 $a_{n+1}=a_{n}+5$
3,8,18,38,78,158 Add 5, Add 10, Add 20 etc.
5,8,14,16,40,88 Add 3, Add 6, Add 12, Add 24 etc.

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Jada walks up to a tank of water that can hold up to 10 gallons.When it is active, a drain empties water from the tank at a cons

worty [1.4K]

Answer:

Part A)The amount of water in the tank is changing at -2/3 gallons per minute. 

Part B) it will take 7.5 minutes for the tank to drain completely.

Part C) The water tank was completely full 4.5 minutes before Jada arrived.

Step-by-step explanation:

Information fetching:

Tank of water can hold up-to 10 gallons.

When it is active, a drain empties water from the tank at a constant rate.
7 gallons of water present in the tank when Jade first saw
5 gallons of water left after 3 minutes

Part A) At what rate is the amount of water in the tank changing?

As the gallons were decreased from 7 to 5 in three minutes. It means in three minutes, 2 gallons were decreased.

So, gallons per minute change would be -2/3 gallons per minute. Hence, the amount of water in the tank is changing at -2/3 gallons per minute. 

Note: negative sign indicates the number of gallons of water are decreasing.

Part B) How many more minutes will it take for the tank to drain completely.

Let 'm' be the number of minutes will it take for the tank to drain completely.

As,

(2/3 gallons per minute) (m minutes) = 5 gallons

So,

m = 5 (3/2)

= 15/2

= 7.5 minutes

So, it will take 7.5 minutes for the tank to drain completely.

Part C) How many minutes before Jada arrived was the water tank completely full

As tank of water can hold up to 10 gallons. So, the tank of water is full when there is 10 gallons of water. So, this is 3 gallons of water more than the total 7 number of gallons at the time when Jada arrived.

As Jada arrived when the tank had left 7 gallons.

Let 'm' be the number of minutes before Jada arrived when the water tank was completely full.

So,

(2/3) (m) = 3

m = 3(3/2) = 9/2

= 4.5 minutes

So, the water tank was completely full 4.5 minutes before Jada arrived.

Keywords: time rate of change, time

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3 years ago

Marla writes the problem, 628 divided by 1300.

Maslowich

Answer:

628/1300

Step-by-step explanation:

These are what would represent her problem..

8 0

3 years ago

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Danielle earns an 8.25% commission on everything she sells at the electronics store where she works. She also earns a base salar

Sauron [17]

Lets begin with our y=mx+b, our constant(b) is 800 that she earns as a salary, our x represents the amount she sells, m then represents the commission which is 8.25% so converting that to a decimal and replacing it as m gets us y = 0.0825x+800. Replace $4500 for x and we have y=0.0825(4500)+800 solve and we get $1171.25

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3 years ago

M : _____ b : _____ Equation : ______ PLEASE HELP ME !!!

fredd [130]

Answer:are you saying mx+b

Step-by-step explanation: hopefully that helps you mark me brainlest please

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3 years ago

A recent study showed that the length of time that juries deliberate on a verdict for civil trials is normally distributed with

tia_tia [17]

Answer:

Probability that deliberation will last between 12 and 15 hours is 0.1725.

Step-by-step explanation:

We are given that a recent study showed that the length of time that juries deliberate on a verdict for civil trials is normally distributed with a mean equal to 12.56 hours with a standard deviation of 6.7 hours.

Let X = length of time that juries deliberate on a verdict for civil trials

So, X ~ N( $\mu = 12.56, \sigma^{2} = 6.7^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 12.56 hours

$\sigma$ = standard deviation = 6.7 hours

So, Probability that deliberation will last between 12 and 15 hours is given by = P(12 hours < X < 15 hours) = P(X < 15) - P(X $\leq$ 12)

P(X < 15) = P( $\frac{X-\mu}{\sigma}$ < $\frac{15-12.56}{6.7}$ ) = P(Z < 0.36) = 0.64058

P(X $\leq$ 12) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{12-12.56}{6.7}$ ) = P(Z $\leq$ -0.08) = 1 - P(Z < 0.08)

= 1 - 0.53188 = 0.46812

Therefore, P(12 hours < X < 15 hours) = 0.64058 - 0.46812 = 0.1725

Hence, probability that deliberation will last between 12 and 15 hours is 0.1725.

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3 years ago