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tester [92]
3 years ago
14

Draw a line representing the "rise" and a line representing the "run" of the line. State

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0

I can't plot it for you, but the slope will be the y/x or the rise/run.

You can find the slope by using 2 points of the line and subtracting the (y1-y2)/(x2-x1)

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Lamar is considering two loans.
Varvara68 [4.7K]

Answer:

a.

Loan I's increase was 0.03 percentage points greater than Loan H's

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Is the following relation a function?<br><br> x y<br> −1 −2<br> 2 3<br> 3 1<br> 6 −2
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Yes because no same x-valu resulted in different y-values.
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Solve for x. x3 =−125
mafiozo [28]

Answer:

x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)

Step-by-step explanation:

Solve for x:

x^3 = -125

Taking cube roots gives 5 (-1)^(1/3) times the third roots of unity:

Answer:  x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)

6 0
3 years ago
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
From midnight to 2:00 am, the temperature rose 1.15°C each hour. If the temperature at 2:00 am was -2.7°C, what was the temperat
malfutka [58]

Answer: -5 degrees Celsius

Step-by-step explanation:

Temp at 2:00am = -2.7

2:00am is two hours after midnight

During that time the temperature has risen by 1.15 degrees every hour so has risen in total by:

1.15x2 = 2.3 degrees

-2.7-2.3=-5

It was -5 degrees at midnight

3 0
3 years ago
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