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amm1812
4 years ago
13

N a chi-square test, the "expected" counts are the values we expect if there is an association between the variables.

Mathematics
1 answer:
horrorfan [7]4 years ago
3 0
The answer would be true gut follow me on sc

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I’ll give brainliest, just help me please :)
Lemur [1.5K]

Answer:

V = 408    SA = 378

Step-by-step explanation:

To find the volume, you need to first find out the area and multiply it by overall length.

A = 1/2 (6)(8)

= 24

Volume = 24 x 17

= 408

Surface Area

SA = Front and Back + Right Side + Left Side + Bottom

= 2 [1/2 (6) (8)] + (17 x 10) + (3 x 8) + (17 x 8)

= 2 (24) + 170 + 24 + 136

= 48 + 170 + 24 + 136

= 378

6 0
3 years ago
Solve the following eqation: 4m - 12 = 0
OLEGan [10]

Answer:

m=3

Step-by-step explanation:

Move the 12 over to the other side so it will be 4m=12, then divide each side by 4 to get m=3

8 0
2 years ago
Read 2 more answers
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
Please help and please say the formula!!
Damm [24]

Answer:

B

Step-by-step explanation:

Formula: 4*((15*7)/2) + 15^2

This is the area of the four triangles combined (210 cm^2) plus the area of the square (225 cm^2)

8 0
3 years ago
Simplify each expression:<br> -(14 + x)
bearhunter [10]

Answer:

-14-x

Step-by-step explanation:

Distribute the negative.

7 0
3 years ago
Read 2 more answers
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