First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
Answer:
k=8
Step-by-step explanation:
have a good day
Answer:
Option B - 2
Step-by-step explanation:
We have given, the length of a spring when it’s at rest is measured to be 0.56 centimeter.
We have to find, how many significant figures are there in this measurement?
Solution :
The rules to get the significant figure are
- Non-zero digits are always significant.
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion ONLY are significant.
The given measurement is 0.56 cm.
It has two trailing zeros in the decimal i.e. 5 and 6.
There are only two significant figures.
Therefore, Option B is correct.
The answer is 20.4 you just multiply 1.70 by 12
