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kap26 [50]
2 years ago
12

Look at the graph below. Is it a function or not a function? Explain your reasoning.​

Mathematics
1 answer:
navik [9.2K]2 years ago
6 0

Answer:

not a function because it dont cross the axis

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1) x+30 = 40
soldier1979 [14.2K]

1)x+30=40

x=40-30

Answer :x=10

2)30-20+2x=10

10+2x=10

2x=0

Answer: x=0

3)3x-10+13=-2x+28

3x+3=-2x+28

3x+2x+3=28

3x+2x=28-3

5x=28-3

5x=25

x=5

4)13x-23-45=-7x+12

13x-68=-7x+12

13x+7x-68=12

13x+7x=12+68

20x=12+68

20x=80

x=4

5)2(x+4)=10x+24

2x+8=10x+24

2x-10x+8=24

2x-10x=24-8

-8x=24-8

-8x=16

x=-2

6)3(x-5)=1-(2x-4)

3x-15=1-(2x-4)

3x-15=1-2x+4

3x-15=5-2x

3x+2x-15=5

3x+2x=5+15

5x=5+15

5x=20

x=4

7)5x-10=15

5x=15+10

5x=25

x=5

8)x+4=x+6

4=6

no solution

PLEASE MARK ME AS BRAINLIEST

4 0
3 years ago
PLEASE HELP ME!!! I WILL GIVE ALL THESE POINTS
WINSTONCH [101]
<h2>Answer and Explanation to questions 13,14,15</h2>

13) \mathbf{\overline{XY}\cong\overline{CD}}        as given in the question.

14) \mathbf{\overline{XY}\cong\overline{YZ}}          Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.

15) \mathbf{\overline{CD}\cong\overline{YZ}}

\because\overline{\textrm{XY}}\cong\overline{\textrm{CD}} and \overline{\textrm{XY}}\cong\overline{\textrm{YZ}} . So, \overline{\textrm{CD}}\cong\overline{\textrm{YZ}}

<h2>Answer and Explanation to questions 16,17,18</h2>

∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°

And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.

∠3 + ∠1 = 180°    .............(i)

∠1 + ∠2 = 180°    .............(ii)

subtracting equation (i) and (ii) will give ∠3 = ∠2   ..........(iii)

15) ∠3 is supplementary to ∠1                        as given in the question

16) ∠2 is supplementary to ∠1                        as shown be equation (ii)

18) ∠3 ≅ ∠2                                                      as shown by equation (iii)

<h2>Answer and Explanation to questions 19</h2>

∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180°   .......(i)

∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180°   .......(ii)

subtracting equation (i) and (ii)

∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)

∠3 + ∠4 - ∠4 - ∠5 = 180°-180°

∠3 - ∠5 = 0

∴ ∠3 = ∠5     (Hence Proved)

4 0
3 years ago
Need help with 2 math questions pls help me for 20 points.
s344n2d4d5 [400]
The answers are A and B
7 0
3 years ago
Use the law of cosines to write an expression equivalent to b
andrezito [222]

Given:

A triangle ABC.

The given expression for b is:

b=\sqrt{m+n-pq}

To find:

The expression that is equivalent to b.

Solution:

According to the Law of Cosines,

b^2=a^2+c^2-2ac\cos B

It can be written as:

b=\sqrt{a^2+c^2-2ac\cos B}              ...(i)

We have,

b=\sqrt{m+n-pq}                                ...(ii)

On comparing (i) and (ii), we get

m=a^2

n=c^2

p=2ac

q=\cos B

Therefore, the required values are m=a^2,n=c^2,p=2ac,q=\cos B.

3 0
3 years ago
Which of the following values is the solution to the equation
Maru [420]

Answer:

x=-14

Step-by-step explanation:

30-(-16)=-30+16=-14=x

x=-14

7 0
3 years ago
Read 2 more answers
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