3 years ago

Why is the answer (A)?

1 answer:

8 0

$\frac{1}{2}x^2+mx-5=0 \\ \\ x= \frac{-mб \sqrt{m^2-4* \frac{1}{2}*(-5) } }{2* \frac{1}{2} }= \frac{-mб \sqrt{m^2+10} }{1}=-mб \sqrt{m^2+10}$

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