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ycow [4]
3 years ago
9

Dave is taking a algebra ii test and comes across this question: you have two die that you will roll. you will sum up the face v

alues and record the sum in a chart. you need to complete 250 trials and find the probability of rolling a sum of 8. unfortunately, he does not have enough time to complete all 250 trials so he is going to make an educated guess. what is his guess and how did he use the law of large numbers to help him
Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
6 0

Answer:  B.)   Dave guessed 0.14. The law of large numbers states that as the number of trials increases the experimental probability approaches the theoretical probability. He determined the theoretical probability would be  

5

36

. With 250 trials he could use the law of large numbers and expect the experimental probability to be near there.

Step-by-step explanation:

sammy [17]3 years ago
5 0
He should guess about 34 times. 

When you are rolling two dice there are 36 probabilities. In order to get an 8, there are 5 possibilities.

2 + 6, 3 + 5, 4 + 4, 5, + 3, 6 + 2

Therefore, the chances of an 8 are 5/36. Multiplying this by 250 gives us about 34.

The law of large numbers helps because it says the more rolls that take place, the more likely we are to get close to the expected value. With 250 rolls we should get pretty close.
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8 0
3 years ago
Write an algebraic expression for the word expression. the quotient of 10 times m and 7
Makovka662 [10]

Answer:

10m/7

Step-by-step explanation:

quotient means division so 10 times m is 10m

and then we will divide 10m and 7

10m/7

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8 0
3 years ago
A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

          p = probability of success

          x = no. of successful trials

          q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

          = 1 - (0.98)⁴

          = 1 - 0.9224

P(X≥1) = 0.0776

4 0
3 years ago
Can somebody tell me what is 3x - 4 = 5?
lions [1.4K]

Answer:

x=3

Step-by-step explanation:

Move the -4 over to the other side.

3x=9

Divide both sides by 3.

x=3

4 0
3 years ago
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The easiest way to do it is graph it and count.
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