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Aloiza [94]
3 years ago
13

I will give you branilest!

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:20 packets

Step-by-step explanation: 30,000/ 1500=20

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A^8-b^8 please factorize this algebaric expression
tigry1 [53]

please follow the pic if you need more help let me know

5 0
3 years ago
Write the equation of the graph
adelina 88 [10]

Answer:

x + 2y - 5 = 0

Step-by-step explanation:

We can see that , the graph passes through (0,2.5) and (5,0) . Therefore the ,

  • x intercept is 5
  • y intercept is 2.5

We can use the intercept form of equation as ,

=> x/a + y/b = 1

=> x/5 + y/2.5 = 1

=> x + 2y/5 = 1

=> x + 2y = 5

=> x + 2y -5 = 0 .

This equation can be verified by plotting the graph .[ Refer to attachment ]

<h3><u>Hence </u><u>the</u><u> </u><u>equation</u><u> of</u><u> </u><u>the</u><u> line</u><u> is</u><u> </u><u>x </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>.</u></h3>

3 0
3 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
Any body I need help plz
schepotkina [342]
I’m not sure but I never went over this
4 0
3 years ago
I am not too sure if I got this right. Can someone double check for me? Will mark brainly.
Vadim26 [7]

Answer:

you are correct

Step-by-step explanation:

5 0
3 years ago
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