It takes 4.3 seconds for the rocket to return to earth.
The equation is:

where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:

We will use the quadratic formula to solve this. The quadratic formula is:

Plugging in our information we have:

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
Answer:
-1/5
Step-by-step explanation:
slope formula:
m = y₂ - y₁ / x₂ - x₁
Two points are given:
(-5, -5) (5, -7)
m = -7 - (-5) / 5 - (-5)
m = -2 / 10
m = -1/5
84 because 36 x 2 =72 and then 1/3 of 36 is 12 and 12+72=84
let's firstly convert the mixed fraction to improper fraction and then divide.
![\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{2}\div 4\implies \cfrac{5}{2}\div \cfrac{4}{1}\implies \cfrac{5}{2}\cdot \cfrac{1}{4}\implies \cfrac{5}{8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%204%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%20%5Ccfrac%7B4%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B1%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B8%7D)