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3241004551 [841]
3 years ago
6

A quadtratic equation that has x intercepts of -8,0 and 2,0 and has a vertical stretch of 3

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

f(x) = 3(x + 8)(x - 2)

Step-by-step explanation:

The intercept form of a quadratic function is y = a(x - r)(x - s), where r and s are the x-intercepts and a is the vertical stretch/compression factor.

If the intercepts are at (-8, 0) and (2, 0), and the vertical stretch is 3, just substitute these values into the intercept form formula, and you're done!

Please mark as Brainliest! :)

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8.<br> Find the arc length of a central angle of 7pi/3 in a circle whose radius is<br> 3inches
pashok25 [27]

\textit{arc's length}\\\\ s = r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ \theta =\frac{7\pi }{3}\\ r=3 \end{cases}\implies s=(3)(\frac{7\pi }{3})\implies s=7\pi \implies s\approx 21.99~in

4 0
2 years ago
F(x)=-9x^2-2x and g(x)=3x^2+6x-9, find (f-g)(x) and (f-g)(-4)
Sergio039 [100]

Answer:

(f-g)(x) = -12x^{2} - 8x + 9

(f-g)(-4) = -151

Step-by-step explanation:

To find f-g(x) we subtract the common terms. So

f(x) = -9x^{2} - 2x

g(x) = 3x^{2} + 6x - 9

(f-g)(x)

(f-g)(x) = f(x) - g(x) = -9x^{2} - 2x - (3x^{2} + 6x - 9) = -9x^{2} - 2x - 3x^{2} - 6x + 9 = (-9 - 3)x^{2} + (-2 - 6)x + 9 = -12x^{2} - 8x + 9

(f-g)(-4)

(f-g)(x) = -12x^{2} - 8x + 9

We replace x by -4

(f-g)(-4) = -12(-4)^{2} - 8(4) + 9= -151

(f-g)(-4) = -151

5 0
3 years ago
7(y – 8) + 24 = x(y – 6)
ICE Princess25 [194]

Answer:y = y = (32 - 6x)/(7 - x)

Step-by-step explanation:

1. Distribute -> 7y - 56 + 24 = xy - 6x

2. Add Like Terms -> 7y - 32 = xy - 6x

3. Collect Like Terms -> 7y - xy = 32 - 6x

4. Factor Out the "y" -> y(7 - x) = 32 - 6x

5. Divide Out the Left "x" -> y = (32 - 6x)/(7 - x)

8 0
2 years ago
Ashley was 98 pounds one year ago. If she now weighs 112 pounds, what is the percent increase in her weight?
Sever21 [200]
B.14.2 because you subtract the 98 to the 112
5 0
3 years ago
Read 2 more answers
Ivan will rent a car for the weekend. He can choose one of two plans. The first plan has no initial fee, but costs $0.90 per mil
borishaifa [10]

Answer:

$337.50

Step-by-step explanation:

The computation of the number of miles need to drive for determining the same cost is given below:

Let us assume the miles be x

So for the first plan, the equation is

= $0.90x

And for the second plan, the equation is

= $75 + $0.70x

Now equate this

0.90x = $75 + 0.70x

0.90x - 0.70x = $75

0.20x = $75

x = $75 ÷ 0.20

= 375 miles

Now the same cost would be

For plan A and plan B

0.90x = $75 + 0.70x

0.90(375) = $75 + 0.70(375)

$337.5 = $75 + $262.50

$337.50 = $337.50

7 0
2 years ago
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