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3 years ago

11

A baseball team has 2 first basemen, 3 second basemen, and 2 third basemen. How many combinations of three are possible?

1 answer:

Dahasolnce [82]3 years ago

3 0

Multiply 3 by 2 then that answer divide by 2 hope this helped

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TRUE or FALSE. In a randomly generated list of numbers from 0 to 5, the chance that each number can occur is 1/5 .

mel-nik [20]

Thank you for posting your question here at brainly. Feel free to ask more questions.

<span>The best and most correct answer among the choices provided by the question is FALSE.</span><span>
</span><span>
<span>Hope my answer would be a great help for you.</span></span>

3 0

3 years ago

Read 2 more answers

What is the place value of the 9 in 219, 775?

Lady_Fox [76]

B) thousands

5 is ones
7 is tens
7 is hundreds
9 is thousands
1 is ten thousands
2 is hundred thousands.

7 0

3 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

What 30+30+30+4+60+9+80

mihalych1998 [28]

Answer:

243

Step-by-step explanation:

3 0

3 years ago

Convert 5.6 into vulgar fraction

zheka24 [161]

Answer:

The answer is 28/5

Step-by-step explanation:

5.6 can be written as 56/10 into vulgar fraction.

Thus, The answer is 56/10 = 28/5

<u>-TheUnknownScientist 72</u>

8 0

2 years ago