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3 years ago

A baseball team has 2 first basemen, 3 second basemen, and 2 third basemen. How many combinations of three are possible?

Mathematics

1 answer:

Dahasolnce [82]3 years ago

3 0

Multiply 3 by 2 then that answer divide by 2 hope this helped

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Some one help me on this one

aleksandrvk [35]

The answer is III only, or D.

We can start to solve this by knowing what the HL theorem means. The HL theorem, like its name implies, shows says that if a hypotenuse and leg of a triangle are congruent to the hypotenuse and leg of a different triangle, then the triangles are congruent. The only triangle that we see a hypotenuse congruent in is in figure III. In figure II, those congruent sides are both legs while in figure I we just see 2 congruent angles. Now in figure III, we can also see that two legs are congruent because of the reflexive property. That means that the answer is III, or D.

5 0

3 years ago

Pang dagdag points niyo.... sagutan niyo nalang ng tamang sagot, yung tamang sago i high rate ko......

Elena-2011 [213]

Answer:

26/5

Step-by-step explanation:

(2)(2)(4)/5 −8+10

(4)(4)/5−8+10

=16/5−8+10

=−24/5+10

=26/5

Alternate form

5.2

5 0

3 years ago

Read 2 more answers

Kendra is making a large salad for a party. She buys lettuce for $2.25 per pound and tomatoes for $2.65 per pound. She spends at

PSYCHO15rus [73]

2.25x + 2.65y > = 8 (thats greater then or equal)

3 0

4 years ago

The table represents a proportional relationship. Give the constant of proportionality, and write an equation that represents th

nignag [31]

Answer:

The constant is: 3.14

Multiplying 2 by 3.14 which would get you to 6.28

Multiply each one by 3.14

3 0

3 years ago

Mr. Akika has 30 24-cent and 33-cent stamps all told. The stamps are worth $8.91. How many of each kind of stamp does he have?

riadik2000 [5.3K]

Answer:

24-cent: 11
33-cent: 19

Step-by-step explanation:

I find it easiest to solve these using the variable to represent the number of the most-expensive item. Let x represent the number of 33-cent stamps. Then the total value (in cents) is ...

33x +24(30 -x) = 891

9x = 171 . . . . . . . . . . . . . subtract 24(30), collect terms

x = 19 . . . . . . . . . . . . divide by 9

30-x = 11 . . . . . . . find the number of 24-cent stamps

Mr. Akika had 11 24-cent stamps and 19 33-cent stamps.

_____

<em>Additional comment</em>

You seem to have several of these to solve. They all have a similar solution.

If we let x represent the number of higher-value items, N, the total number of items, V the total value, and v1 and v2 the individual values (v2 > v1), the equation is ...

v2(x) +v1(N -x) = V

x(v2 -v1) = V -v1·N

x = (V -v1·N)/(v2 -v1) . . . . generic solution

Using this formula in the problem here, we find ...

x = (891 -24(30))/(33 -24) = 171/9 = 19 . . . as above

7 0

2 years ago