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Simora [160]
2 years ago
5

At lunch, Darius ordered a slice of pizza for $2.75, French fries for $1.20, and a drink for $1.35. Sale tax was $0.37. If Dariu

s paid for his lunch with a $10 bill, how much change did he get back?
Mathematics
2 answers:
Ulleksa [173]2 years ago
8 0

Answer:

he gets 4.33 dollars back

Step-by-step explanation:

add 2.75+1.20+1.35+0.37= 5.67

10-5.67=4.33 $

Ipatiy [6.2K]2 years ago
5 0

Answer:

4.33

Step-by-step explanation:

if u add 2.75 1.20 and 1.35 plus the additional 37 cents u get 5.67 then u do 10- 5.67

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3 years ago
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0
2 years ago
The sum of two positive numbers is 588. minimize the sum of the first and three times the second
Marianna [84]

9514 1404 393

Answer:

  {587, 1}

Step-by-step explanation:

The sum will be minimized when the second number is as close to zero as is allowed. If the numbers must be positive integers, the sum is minimized when the numbers are {587, 1}.

If the numbers may be real numbers, then the values that minimize the sum are {588-, 0+}

_____

The "cost" of taking a unit from the sum 588 and assigning it to the second number is that the sum of first and 3 times the second goes up by 3. In order to minimize that sum, the second number must be minimized.

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3 years ago
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Answer:

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never [62]
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57760

The answer is A.
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