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3 years ago

If the ratio between the radii of the two spheres is 3:7, what is the ratio of their volumes?

1 answer:

4 0

Given that the dilation factor or scale factor between the two spheres is equal to 3:7, the ratio between their volumes is calculated by cubing the numbers in the ratio. That is,
3³:7³
This operation will give us an answer of 27:343

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Suppose that you are taking a T/F exam and you have no idea at all about the answers to the last three questions. You choose ans

podryga [215]

Answer:

0.375, 0.125, 0.5

Step-by-step explanation:

given that you are taking a T/F exam and you have no idea at all about the answers to the last three questions.

Probability for correct guess = 0.5 remains constant for each of the three questions

X - no of questions is binomial with n =3 and p = 0.5

1) the probability that you guessed right on exactly one of the three questions

= P(X=1)

= $3C1(0.5)^3 = 0.375$

2) the probability that you guessed right on zero of the three questions

= $P(X=0)\\= 0.5^3=0.125$

3) the probability that you guessed right on at least two of the questions

= $P(x=3)+P(2)\\= 1-0.5\\=0.5$

7 0

3 years ago

A bathtub can hold 80 gallons of water. The faucet flows at a rate of 4 gallons per minute. What percentage of the tub will be f

krok68 [10]

Answer:

120

Step-by-step explanation:

80 divided by 2 is 40 plus 80 would be 120 which is 6 minutes worth of filling

6 0

3 years ago

PLEASE HELP ME ASAP!!!

tangare [24]

AnswerAnswer: C

Step-by-step explanation:c

8 0

2 years ago

Read 2 more answers

When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v squared w

Sati [7]

Answer:

Step-by-step explanation:

The model fo the shell is given by the following equation of equilibrium:

$\Sigma F = -b\cdot v^{2} - m\cdot g = m\cdot \frac{dv}{dt}$

This first-order differential equation has separable variables, which are cleared herein:

$\int\limits^t_{0\,s} \, dt = -\frac{m}{b} \int\limits^{0\,\frac{m}{s} }_{600\,\frac{m}{s} } {\frac{1}{ v^{2}+\frac{m}{b}\cdot g } } \, dv$

The solution of this integral is:

$t = -\frac{m}{2b}\cdot \left[\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }\right) - \tan^{-1} \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }\right)\right]$

$\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } } \right)=-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)$

$\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\right]$

$v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m} \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m} \right) }\right]$