The answer is the fourth one
Problem set A: A=6 and B=2
6=AxB^0 [6=6x1]
24=AxB^2= [24=6x2^2]
Problem set B: A=2 and B=4
32=AxB^2 [32=2x4^2]
128=AxB^3 [128=2x4^3]
Slope-intercept form: y = mx + b [m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y) or the point where the line crosses through the y-axis]
To find the slope, use the slope formula (m):
and plug in the two points
(6, 8) = (x₁, y₁)
(9, 6) = (x₂, y₂)


Now that you found the slope, plug it into the equation
y = mx + b
To find b, plug in one of the points, I will use (6, 8)

8 = -4 + b Add 4 on both sides
12 = b Now plug in b into the equation

Answer:
14! So a
Step-by-step explanation:
Answer:
Option 4.
Step-by-step explanation:
The vertex form of a parabola is
... (1)
where, a is a constant (h,k) is vertex.
The given function is

The vertex of the function is (0,0) and it goes through (-2, 4) and (2, 4).
It is given that the vertex of function g(x) is at (5,2).
Substitute h=5 and k=2 in equation.

g(x) is passes through (3, 6).
.... (2)


Divide both sides by 4.

Substitute a=1 in equation (2).


The function g(x) is
.
Therefor, the correct option is 4.