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dybincka [34]
3 years ago
7

I need help with this question please

Mathematics
2 answers:
blondinia [14]3 years ago
7 0

Answer:

6 is already pointed

9<V83 <10   cause 9=V81 , 10 =V100

6<V40<7       cause 6=V36,7= V49

V64=8

7<7.5<8

Step-by-step explanation:

Shtirlitz [24]3 years ago
3 0

Answer: 6 goes on 6/// 83 goes on 9///// 40goes on 6///// 64 goes on8///and the 7.5 will go between 7 and 8

Step-by-step explanation:

go onto a calculator and type in the number and decide it by the square root

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Answer:

rosemary needs to maintain 65 mph

Step-by-step explanation:

3 0
2 years ago
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A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4
LUCKY_DIMON [66]

Answer:

1. q=(\dfrac{45}{p})^{\frac{2}{3}}

2. E_d=-\dfrac{2}{3}

Step-by-step explanation:

The given demand equation is

p=\dfrac{45}{q^{1.5}}

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

q^{1.5}=\dfrac{45}{p}

Using the properties of exponent, we get

q=(\dfrac{45}{p})^{\frac{1}{1.5}}      [\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]

q=(\dfrac{45}{p})^{\frac{2}{3}}

Therefore, the required equation is q=(\dfrac{45}{p})^{\frac{2}{3}}.

Part 2 :

q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}

Differentiate q with respect to p.

\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})

\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})

\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})

Formula for price elasticity of demand is

E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}

E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}

Cancel out common factors.

E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}

Using the properties of exponents we get

E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})

E_d=-\dfrac{2}{3}(p^{0})

E_d=-\dfrac{2}{3}

Therefore, the price elasticity of demand is -2/3.

3 0
2 years ago
Question is in the image, thank you
Alex787 [66]

sin H = Opposite / Hypotenuse

sin H = 5/13

sin H = 0.384615

<H = 22.6198

<H = 23 (nearest degree)

Answer is first one.

23

6 0
3 years ago
Find the slope of the line through the pair of points.<br> (17,-7) and (13,-4)]
Marysya12 [62]

Answer:

3/4

Step-by-step explanation:

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Here is an expression: 3⋅2 Evaluate the expression when is 1. Evaluate the expression when is 4.
zmey [24]

Answer:

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2.) 14

Step-by-step explanation:

As given,

the expression - 3x + 2

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⇒ 3x + 2 = 3(1) + 2 = 3+2 = 5

2.)

Evaluate the expression when x is 4

⇒ 3x + 2 = 3(4) + 2 = 12+2 = 14

3 0
3 years ago
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