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3 years ago

I need help with this question please

Mathematics

2 answers:

blondinia [14]3 years ago

7 0

Answer:

6 is already pointed

9<V83 <10 cause 9=V81 , 10 =V100

6<V40<7 cause 6=V36,7= V49

V64=8

7<7.5<8

Step-by-step explanation:

Shtirlitz [24]3 years ago

3 0

Answer: 6 goes on 6/// 83 goes on 9///// 40goes on 6///// 64 goes on8///and the 7.5 will go between 7 and 8

Step-by-step explanation:

go onto a calculator and type in the number and decide it by the square root

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Rosemary is driving to Chicago, and she is 84 miles away. She wants to arrive in 1.5 hours. What rate of speed will she have to

Olegator [25]

Answer:

rosemary needs to maintain 65 mph

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

2 years ago

Question is in the image, thank you

Alex787 [66]

sin H = Opposite / Hypotenuse

sin H = 5/13

sin H = 0.384615

<H = 22.6198

<H = 23 (nearest degree)

Answer is first one.

6 0

3 years ago

Find the slope of the line through the pair of points.<br> (17,-7) and (13,-4)]

Marysya12 [62]

Answer:

3/4

Step-by-step explanation:

(17,-7) And (13,-4). First take -4 and subtract it from-7. When you do that you get 3. Then Subtract 13-17. You get 4. Write 3 and 4 as a fraction. 3/4. The 3 is the x-value and the 4 is the y value. So 3/4 is your slope

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3 years ago

Here is an expression: 3⋅2 Evaluate the expression when is 1. Evaluate the expression when is 4.

zmey [24]

Answer:

1.) 5

2.) 14

Step-by-step explanation:

As given,

the expression - 3x + 2

1.)

Evaluate the expression when x is 1

⇒ 3x + 2 = 3(1) + 2 = 3+2 = 5

2.)

Evaluate the expression when x is 4

⇒ 3x + 2 = 3(4) + 2 = 12+2 = 14

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3 years ago