Hello.
This is how I would work out this question, please let me know if there are any flaws.
Write an equation:
9x+24+30x=180
We know that a straight line is an 180 degree angle, so both angles should have a sum of 180.
Now, we solve algebraically.
9x+24+30x=180
39x+24=180
39x+24-24=180-24
39x=156
39x/39=156/39
x= 4
Substitute 4 for x in each expression.
9x+24
9(4)+24
36+24
60
So, the first angle is 60 degrees.
30x
30(4)
120
The second angle is 120 degrees.
Angle AEB is opposite angle DEC, so that means it has the same value of 60 degrees.
∴The answer is 60 degrees.
Please check it over and try other ways of solving to make sure I have the correct answer. I tried my best, hope this helps!
Answer:
The answer to your question is
a) 
b) distance = 2400 mi
Step-by-step explanation:
a) 8 mi/s convert to mi/min

b) 
distance = speed x time
distance = 
distance = 2400 mi
You should reinvest it. Compounding means that if you put $10 in and it gives you 110% of your investment, then you’ll receive $11. If you reinvest it and it gives 110% again, you’ll have $12.10. This will continue to accrue until you stop investing. If something doesn’t compound, you’ll only get the extra $1 over and over.
<h3>

</h3>
Answer:
Solution given
Cos
consider Pythagorean theorem

Subtracting
both side

doing square root on both side we get

Similarly

Substituting value of 
we get

<h3>Solving numerical</h3>




Since
In IVquadrant sin angle is negative

First find the time that the ball is level with the top of the building on its descent. You can do this by solving 280 = -16^2 + 48t + 280 for t. This gives t = 3 seconds .
Then when the ball reaches the ground the time t is obtained by solving 0 = -16t^2 + 48t + 280 This gives t = 5.94 seconds.
Answer in interval notation is (3, 5.94].