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Andreas93 [3]
3 years ago
6

How I do 4 boxes that weighed total of 34 kilograms if each box had the same amount

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0
34/4=8.5 kilograms per box
Blizzard [7]3 years ago
4 0
Each box would have exactly 8.5 kilograms each in them. Hope this helps mate =)

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I need help
dangina [55]

Answer:

a)  x =3 and x=5

c)  x =-1 and x = \frac{-7}{3}

i)  x =0 and  x = \frac{-9}{2}

Step-by-step explanation:

a)

Given that the quadratic equation

    x² - 8x +15 =0

The factors of 15 = 5 × 3

   x² - 5x -3x +15 =0

  x(x -5) -3(x-5) =0

  (x-3)(x-5) =0

x =3 and x=5

c)

  3 x² + 10 x +7 =0

⇒   3x² + 3x + 7x +7 =0

⇒   3x (x +1) +7(x+1) =0

⇒  (x+1) ( 3 x +7) =0

⇒  x =-1 and x = \frac{-7}{3}

i)

     2 x ² + 9 x =0

⇒ x( 2 x + 9) =0

⇒ x =0 and 2 x = -9

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4 0
3 years ago
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What is the equation, in standard form of the parabola that contains the following points? (-2,18), (0,2), (4,42)
Vladimir79 [104]

Answer: y = 3x^{2} - 2x + 2

Step-by-step explanation:

The equation in standard form of a parabola is given as :

y = ax^{2}  + bx + c

The points given are :

( -2 , 18 ) , ( 0,2) , ( 4 , 42)

This means that :

x_{1} = -2

x_{2} = 0

x_{3} = 4

y_{1} = 18

y_{2} = 2

y_{3} = 42

All we need do is to substitute each of this points into the equation , that is , x_{1} and y_{1} will be substituted to get an equation , x_{2} and y_{2} will be substituted to get an equation and x_{3} , y_{3} will also be substituted to get an equation also.

Starting with the first one , we have :

y = ax^{2}  + bx + c

18 = a[(-2)^{2}] + b (-2) + c

18 = 4a  - 2b + c

Therefore :

4a - 2b + c = 18 ................ equation 1

substituting the second values , we have

2 = a (0) + b ( 0) + c

2 = c

Therefore c = 2   ............... equation 2

also substituting the third values , we have

42 = a[(4)^{2}] + b (4) + c

42 = 16a + 4b + c

Therefore

16a + 4b + c = 42  ........... equation 3

Combining the three equations we have:

4a - 2b + c = 18 ................ equation 1

c = 2   ............... equation 2

16a + 4b + c = 42  ........... equation 3

Solving the resulting linear equations:

substitute equation 2 into equation 1 and equation 3 ,

substituting into equation 1 first we have

4a - 2b + 2 = 18

4a - 2b = 16

dividing through by 2 , we have

2a - b = 8 ............... equation 4

substituting c = 2 into equation 3 , we have

16a + 4b + c = 42

16a + 4b + 2 = 42

16a + 4b = 40

dividing through by 4 , we have

4a + b = 10 ................ equation 5

combining equation 4 and 5 , we have

2a - b = 8 ............... equation 4

4a + b = 10 ................ equation 5

Adding the two equations to eliminate b , we have

6a = 18

a = 18/6

a = 3

Substituting a = 3 into equation 4 to find the value of b , we have

2(3) - b = 8

6 - b = 8

b = 6 - 8

b = -2

Therefore :

a = 3 , b = -2 and c = 2

Substituting these values into the equation of parabola in standard form , we have

y = 3x^{2} - 2x + 2

3 0
3 years ago
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