So you can use substitution...which is where you have Y all alone on one side of your equation and then plug it in to the other equation...2x-5=-3x+10 and you.solve for X. So x= 3. Then plug 3 into one of the original equations... Y=2(3)+5. So Y= 11.
Answer: It’s 1
Explanation: it’s 1
Answer:
the top one
Step-by-step explanation:
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.