The minimum distance between the asteroid and the sun is 10 - 6 =4
The given hyperbolic path defined as
divide both the sides by 576,
The general equation of
hyperbola is written as
;
Compare with above mention equation
Here
The distance between the asteroid and the sun is seen by figure -1
or
⇒c =10
The minimum distance between the asteroid and the sun is 10 -6 =4
Answer:
= -14x
Step-by-step explanation:
Since the equation is saying to subtract 10x, we are going to change the minus sign to a addition sign and change positive 10 to negative and continue the rest.
Answer:
<h3>
x = 27°</h3>
Step-by-step explanation:
2x + 2x + 72° = 180°
4x = 108°
x = 27°
Answer:
Wednesday (9 weeks later) = 10th October.
Step-by-step explanation:
We label the days with the initials of the names.
M= 4
D = 7
B = 6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it would be 84 days after this event.
18+ 84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th October
We can check 84 days = 9 weeks
13 days in July makes 31st july
31 days in Aug makes 31st Aug
30 days in Sept makes 30th Sept
= 74 days + 10 days = 84
10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.
Base Surface Area = 2π×22 = 25.132741228718 feet2
Lateral Surface Area = 2π×2×15 = 188.49555921539 feet2
Total Surface Area = 213.62830044411 feet2
(Figure A)
Base Surface Area = 2π×52 = 157.07963267949 feet2
Lateral Surface Area = 2π×5×17 = 534.07075111026 feet2
Total Surface Area = 691.15038378975 feet2
(Figure B)
Base Surface Area = 2π×82 = 402.12385965949 feet2
Lateral Surface Area = 2π×8×22 = 1105.8406140636 feet2
Total Surface Area = 1507.9644737231 feet2
(Figure C)
